4(x^2-33)=-37x

Solution for 4(x^2-33)=-37x equation:

4(x^2-33)=-37x

We move all terms to the left:

4(x^2-33)-(-37x)=0

We multiply parentheses

4x^2-(-37x)-132=0

We get rid of parentheses

4x^2+37x-132=0

a = 4; b = 37; c = -132;
Δ = b2-4ac
Δ = 372-4·4·(-132)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-59}{2*4}=\frac{-96}{8}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+59}{2*4}=\frac{22}{8}
=2+3/4
$